Optimal. Leaf size=58 \[ \frac{i c^2 (a+i a \tan (e+f x))^5}{5 a f}-\frac{i c^2 (a+i a \tan (e+f x))^4}{2 f} \]
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Rubi [A] time = 0.100748, antiderivative size = 58, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 3, integrand size = 31, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.097, Rules used = {3522, 3487, 43} \[ \frac{i c^2 (a+i a \tan (e+f x))^5}{5 a f}-\frac{i c^2 (a+i a \tan (e+f x))^4}{2 f} \]
Antiderivative was successfully verified.
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Rule 3522
Rule 3487
Rule 43
Rubi steps
\begin{align*} \int (a+i a \tan (e+f x))^4 (c-i c \tan (e+f x))^2 \, dx &=\left (a^2 c^2\right ) \int \sec ^4(e+f x) (a+i a \tan (e+f x))^2 \, dx\\ &=-\frac{\left (i c^2\right ) \operatorname{Subst}\left (\int (a-x) (a+x)^3 \, dx,x,i a \tan (e+f x)\right )}{a f}\\ &=-\frac{\left (i c^2\right ) \operatorname{Subst}\left (\int \left (2 a (a+x)^3-(a+x)^4\right ) \, dx,x,i a \tan (e+f x)\right )}{a f}\\ &=-\frac{i c^2 (a+i a \tan (e+f x))^4}{2 f}+\frac{i c^2 (a+i a \tan (e+f x))^5}{5 a f}\\ \end{align*}
Mathematica [A] time = 3.04275, size = 80, normalized size = 1.38 \[ \frac{a^4 c^2 \sec (e) \sec ^5(e+f x) (-5 \sin (2 e+f x)+5 \sin (2 e+3 f x)+\sin (4 e+5 f x)+5 i \cos (2 e+f x)+5 \sin (f x)+5 i \cos (f x))}{20 f} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.003, size = 50, normalized size = 0.9 \begin{align*}{\frac{{a}^{4}{c}^{2}}{f} \left ( \tan \left ( fx+e \right ) -{\frac{ \left ( \tan \left ( fx+e \right ) \right ) ^{5}}{5}}+{\frac{i}{2}} \left ( \tan \left ( fx+e \right ) \right ) ^{4}+i \left ( \tan \left ( fx+e \right ) \right ) ^{2} \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.73028, size = 92, normalized size = 1.59 \begin{align*} -\frac{6 \, a^{4} c^{2} \tan \left (f x + e\right )^{5} - 15 i \, a^{4} c^{2} \tan \left (f x + e\right )^{4} - 30 i \, a^{4} c^{2} \tan \left (f x + e\right )^{2} - 30 \, a^{4} c^{2} \tan \left (f x + e\right )}{30 \, f} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 1.0515, size = 351, normalized size = 6.05 \begin{align*} \frac{80 i \, a^{4} c^{2} e^{\left (6 i \, f x + 6 i \, e\right )} + 80 i \, a^{4} c^{2} e^{\left (4 i \, f x + 4 i \, e\right )} + 40 i \, a^{4} c^{2} e^{\left (2 i \, f x + 2 i \, e\right )} + 8 i \, a^{4} c^{2}}{5 \,{\left (f e^{\left (10 i \, f x + 10 i \, e\right )} + 5 \, f e^{\left (8 i \, f x + 8 i \, e\right )} + 10 \, f e^{\left (6 i \, f x + 6 i \, e\right )} + 10 \, f e^{\left (4 i \, f x + 4 i \, e\right )} + 5 \, f e^{\left (2 i \, f x + 2 i \, e\right )} + f\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [B] time = 5.16324, size = 185, normalized size = 3.19 \begin{align*} \frac{\frac{16 i a^{4} c^{2} e^{- 4 i e} e^{6 i f x}}{f} + \frac{16 i a^{4} c^{2} e^{- 6 i e} e^{4 i f x}}{f} + \frac{8 i a^{4} c^{2} e^{- 8 i e} e^{2 i f x}}{f} + \frac{8 i a^{4} c^{2} e^{- 10 i e}}{5 f}}{e^{10 i f x} + 5 e^{- 2 i e} e^{8 i f x} + 10 e^{- 4 i e} e^{6 i f x} + 10 e^{- 6 i e} e^{4 i f x} + 5 e^{- 8 i e} e^{2 i f x} + e^{- 10 i e}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 1.61884, size = 180, normalized size = 3.1 \begin{align*} \frac{80 i \, a^{4} c^{2} e^{\left (6 i \, f x + 6 i \, e\right )} + 80 i \, a^{4} c^{2} e^{\left (4 i \, f x + 4 i \, e\right )} + 40 i \, a^{4} c^{2} e^{\left (2 i \, f x + 2 i \, e\right )} + 8 i \, a^{4} c^{2}}{5 \,{\left (f e^{\left (10 i \, f x + 10 i \, e\right )} + 5 \, f e^{\left (8 i \, f x + 8 i \, e\right )} + 10 \, f e^{\left (6 i \, f x + 6 i \, e\right )} + 10 \, f e^{\left (4 i \, f x + 4 i \, e\right )} + 5 \, f e^{\left (2 i \, f x + 2 i \, e\right )} + f\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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